Class 12

Math

Calculus

Continuity and Differentiability

Differentiate w.r.t. x the function $sin_{3}x+cos_{6}x$

**Solution: **Solution: =$sin_{3}x+cos_{6}x$

differentiate with respect to x

=$δxδ (sin_{3}x+cos_{6}x)$

=$δxδ (sin_{3}x)+δxδ cos_{6}x$

=$3sinxcosx(sinx−2cos_{4}x)$